参考文章1
参考文章2

第一次使用csdn写文章，写得不好还请见谅。（运行环境：python3.6）

下了一个带密码的压缩包文件，作为一个刚学python的新手，想着能不能用python暴力破解它，于是在网上搜了很多资料，看着似乎并不是很麻烦，也想试着自己写一个可以暴力破解的程序，在写的过程中却遇到了各种各样的问题，希望大手们能带带我。遇到的问题如下：

• zipfile和zipfile2似乎都不支持AES解密(https://bugs.python.org/issue9170)
• 在用rarfile暴力破解时即使密码错误也不抛出异常,因此无法用try，except捕获密码

本来是想写一个可以同时暴力破解zip和rar的程序，在试了半天解密zip却一直提示密码错误之后放弃了zip，想着能不能写一个暴力破解rar的程序。

首先是生成字典：要用到itertools模块

import itertools as its
import string

def createDict(path,repeats,words):
	dict = its.product(words,repeat=repeats) 
	'''这里的words是要迭代的字符串，repeats是生成的密码长度，生成的dict是一个返回元组的迭代器'''
	f = open(path,'a')
	for cipher in dict:
		f.write(''.join(cipher) + '\n')
	f.close()

def main():
	numbers = string.digits  #包含0-9的字符串
	path = '输入你的字典路径'
	length = 你要迭代的密码长度
	for i in range(1,length):
		createDict(path,i,numbers)

if __name__=="__main__":
	main()

到这里我们的字典已经生成完毕了，接下来开始暴力破解rar

from threading import Thread
from unrar import rarfile
import os

'''首先我们要读取字典，字典可能太大因此我们采用迭代器'''

def get_pwd(dict_path):
	with open(dict_path,'r') as f:
		for pwd in f:
			yield pwd.strip()

def decode_rar(fp,pwd,extract_path):
	try:
		fp.extractall(extract_path,pwd=pwd) 
	except:
		pass
	else:
		print('the pwd is>',pwd)
'''
事实上我在尝试时似乎从来没有到达过else，这样可能是得不到解压密码的。我的
一种得到密码的想法如下，但是运行效率可能会降低


def decode_rar(fp,pwd,check_file,extract_path):
	fp.extractall(extract_path,pwd=pwd)
	if os.path.exists(check_file):
		print('The pwd is:',pwd)
		exit(0)
其中check_file可以设置为fp.namelist()[0]
并且该方法不能使用多线程，因此速度会降低很多
'''

def main():
	extract_path = '你要解压的路径'
	dict_path = '你的字典路径'
	filename = '你的rar路径'
	fp = rarfile.RarFile(filename)
	pwds = get_pwd(dict)
	'''使用多线程可提高速度'''
	for pwd in pwds:
		t = Thread(target=rar_file,args=(fp,pwd,extract_path))
		t.start()

以上是写程序的思路和遇到的各种坑，代码是手敲的，可能有一些错误，希望能得到谅解和帮助。
下面是一个图形界面的rar解密源代码：(图形只是想练习，运行较慢，建议直接运行上面的函数)

import tkinter as tk
import os
from tkinter import messagebox
from unrar import rarfile
from threading import Thread

def getPwd(dict):
    with open(dict,'r') as f:
        for pwd in f:
            yield pwd.strip()
def slowerDecode(fp,pwd,check_file,extract_path):
    fp.extractall(extract_path,pwd=pwd)
    if os.path.exists(check_file):
        messagebox.showinfo(message="密码："+pwd)
        messagebox.showinfo(message="程序结束")
        messagebox.showinfo(message="密码："+pwd)
        exit(0)
	
def quickDecode(fp,pwd,extract_path):
    fp.extractall(extract_path,pwd=pwd)


def check(obs):
    flag = 1
    for ob in obs:
        if not ob.checkExist():
            flag = 0
            ob.showError()    

    if(not flag):
        return 0
    else:
        for ob in obs:
            if not ob.check():
                flag = 0
                ob.showError()
		
    if (not flag):
        return 0
    else:
        for ob in obs:
            ob.right()
        return 1
		
def main(obs):
    extract_path = obs[0].path_input.get()
    rar_path = obs[1].path_input.get()
    txt_path = obs[2].path_input.get()
    pwds = getPwd(txt_path)
    global var1
    global var2
    if(check(obs)):
        if(var1.get() == 0 and var2.get() == 0):
            messagebox.showerror(message="选择一个选项！！！")
        elif(var1.get() == 0 and var2.get() == 1):
            fp = rarfile.RarFile(rar_path)
            check_file = fp.namelist()[0]
            for pwd in pwds:
                slowerDecode(fp,pwd,check_file,extract_path)
        elif(var1.get() == 1 and var2.get() == 0):
            fp = rarfile.RarFile(rar_path)
            for pwd in pwds:
                t = Thread(target=quickDecode,args=(fp,pwd,extract_path))
                t.start()
            exit(0)
        else:
            messagebox.showerror(message="只选择一个！！！")
        

class FolderPath:
    
    def __init__(self,y=0,error_message="Not exists!",path_input="",text=''):
        self.y = y
        self.error_message = error_message
        self.path_input = path_input
        self.text = text
	
    def createLabel(self):
        label = tk.Label(window,bg="white",font=("楷体",13),width=20,text=self.text)
        cv.create_window(100,self.y,window=label)
    
    def createEntry(self):
    	entry = tk.Entry(window,fg="blue",width="40",bg="#ffe1ff",textvariable=self.path_input)
    	cv.create_window(330,self.y,window=entry)
    
    def show(self):
        self.createLabel()
        self.createEntry()
	
    def showError(self,color="red"):
        label = tk.Label(window,bg="white",fg=color,font=("楷体",13),width="10",text=self.error_message)
        cv.create_window(530,self.y,window=label)
    
    def checkExist(self):
        self.error_message = 'Not exists!'
        if not os.path.exists(self.path_input.get()):
            return 0
        return 1
    
    def check(self):
        if not os.path.isdir(self.path_input.get()):
            self.error_message = 'Not a dir!'
            return 0
        else:
            return 1
    
    def right(self):
        self.error_message = "right path!"
        self.showError('#00FFFF')
	
    
class FilePath(FolderPath):
    def check(self):
        if (self.path_input.get().split('.')[-1] == self.suffix):
            return 1
        else:
            self.error_message = "Not "+self.suffix + '!'
            return 0
    

window = tk.Tk()
window.title('made by qiufeng')
window.geometry('600x300')
cv = tk.Canvas(window,width=600,height=300,bg='white')
cv.pack()

folderpath = FolderPath(y=140,path_input=tk.StringVar(),text="请输入解压路径")
folderpath.show()


rarpath = FilePath(y=60,path_input=tk.StringVar(),text="请输入rar路径")
rarpath.suffix = 'rar'
rarpath.show()

txtpath = FilePath(y=100,path_input=tk.StringVar(),text="请输入字典路径")
txtpath.suffix = 'txt'
txtpath.show()
obs = [folderpath,rarpath,txtpath]

#多选框
var1 = tk.IntVar()
var2 = tk.IntVar()
ck1 = tk.Checkbutton(window,text="直接破解(无法获得密码)",variable=var1)
cv.create_window(150,200,window=ck1)
ck2 = tk.Checkbutton(window,text="慢速(可获得密码)",variable=var2)
cv.create_window(132,230,window=ck2)
button = tk.Button(window,text="确认",command=lambda: main(obs))
cv.create_window(90,260,window=button)

window.mainloop()